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sasho [114]
3 years ago
12

Someone please help asap!!! How do I know where to shade at?

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Shade the top side of the boundary line if you have the inequality symbols > or ≥. Shade the bottom side of the boundary line if you have the inequality symbols < or ≤.

\large\bold\red{Answered By Ayush8928 }

=================•✠•================

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51 participants went on the 7th grade field trip to the national history museum.2/3 of them rode on a large bus.The rest went in
labwork [276]
51 ÷ 3 = 17
17 were in the van
51 - 17 = 34
34 were in the bus
3 0
3 years ago
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How do u find slope on the graph
Shkiper50 [21]

Answer:

you get 2 coordinates x one, y one, x two, and y two and then do rise over run which is y two - y one over x two - x one say x one is 4 and y one is 7 and x two is 8 and y two is 13 you say 13-7=6 and 8-4=4 so it is 6/4 hope that makes sense

7 0
3 years ago
If p(a)=0.24 and p(b)=0.52 and a and b are independent, what is p(a or b)?
Crank
Download the app photo math and there is the answer
3 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
3 years ago
13x + 15=17x-13 solve for the solution
Archy [21]

Answer: x=7

Step-by-step explanation:

Step 1: Subtract 17x from both sides.

13x+15−17x=17x−13−17x

−4x+15=−13

Step 2: Subtract 15 from both sides.

−4x+15−15=−13−15

−4x=−28

Step 3: Divide both sides by -4.

−4x/−4 =−28/−4

x=7

6 0
3 years ago
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