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krek1111 [17]
2 years ago
10

What is the vertex of the graph of the following equation? y = x^2 + 2x-3

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
6 0

Answer:

vertex = (- 1, - 4 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = x² + 2x - 3 ← is in standard form

with a = 1, b = 2 , then

x = - \frac{2}{2} = - 1

Substitute x = - 1 into the equation for corresponding value of y

y = (- 1)² + 2(- 1) - 3 = 1 - 2 - 3 = - 4

vertex = (- 1, - 4 )

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Therefore 4 more rows are needed here

Hope it helps you

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3 years ago
Can I please get an explanation and answer for this problem.
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bekas [8.4K]
Should be B! Hope it helps
5 0
2 years ago
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123
ser-zykov [4K]

First, I'm going to separate factor the expression inside of the square root.

sqrt[ (2/18) * (x^5) ]

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Looking at the x^5, we can separate it into x^2 * x^2 * x^1. The square root of x^2 is x. So, we now also have an x^2 on the outside because there are two x^2s in our expanded form.

ANSWER: (x^2 * sqrt(x)) / 3

(Option 1)

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