What is the vertex of the graph of the following equation? y = x^2 + 2x-3
1 answer:
Answer:
vertex = (- 1, - 4 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
y = x² + 2x - 3 ← is in standard form
with a = 1, b = 2 , then
x = - = - 1
Substitute x = - 1 into the equation for corresponding value of y
y = (- 1)² + 2(- 1) - 3 = 1 - 2 - 3 = - 4
vertex = (- 1, - 4 )
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