Answer:
1.16
2.344
Step-by-step explanation:
A. Arc BC is apart of the diameter. The major arc measures 164 so
Arc BC=16
B. Arc BAC means we find the measures BA then find the measures of arc AC and add them.
Measures of BA is 180.
Measures of AC is 164.
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
The minimum happens at x = -b/2a
x = -30 / 2(3) = -30/6 = -5
Now replace x in the equation with -5 and solve:
3(-5)^2 + 30(-5) +27 = 75 - 150 + 27 = -48
The minimum is at (-5,-48)
First find the vertical distance from Charlie to the plane by subtracting the altitude of Charlie's eyes from the altitude of the plane: 1700-5.2=1694.8 ft. Let d be the distance from Charlie to the plane. Use the trignometric relationship in the right triangle: sin32=1694.8/d. d=3198 ft.
