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lana [24]
3 years ago
14

Mario received y text messages each minute for 10

Mathematics
2 answers:
Rom4ik [11]3 years ago
7 0
D.........................................
NemiM [27]3 years ago
3 0
Probably d, have a good day!! stay safe
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Evaluate the expression:<br> 9 +7(5-2)<br> Using PEDMAS<br><br> yall i suck at math
ANEK [815]

Hello! :)

Let's use PEMDAS.

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

(5-2) = 3 Do parenthesis.

7 × 3 = 21 Multiply with what we got after doing the parenthesis.

9 + 21 = 30 Add with what we had left.

30

Hope this helps!

ELITEDIPER

5 0
4 years ago
Which of the following information about the graph of the relationship is given
katrin2010 [14]

Answer:

there is no gragh

Step-by-step explanation:

6 0
3 years ago
Which of the following is the domain and range of the ellipse with equation x2 + 4y2 – 2x + 16y – 19 = 0?
Nata [24]

The option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7], and the range is R: [–5, 1]

<h3>What is an ellipse?</h3>

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have an ellipse equation:

\rm x^{2}+4y^{2}-2x+16y-19=0

We can write the above equation as:

\rm \dfrac{\left(x-1\right)^{2}}{36}+\dfrac{\left(y+2\right)^{2}}{9}=1

The domain will be:

D: [–5, 7]

The range will be:

R: [–5, 1]

Thus, the option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7] and the range is R: [–5, 1]

Learn more about the ellipse here:

brainly.com/question/19507943

#SPJ1

5 0
2 years ago
How do I verify #15 using fundamental trig identities?
expeople1 [14]

We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

\frac{sin \theta + tan \theta}{1+cos \theta}

Using Quotient identity for tangent function, we will get

\frac{sin \theta+ \frac{sin \theta}{cos \theta}}{1+cos \theta}

\frac{sin \theta cos \theta + sin \theta}{cos \theta(1+cos \theta)}

Taking out sine function from the numerator

=\frac{sin \theta(1+cos \theta)}{cos \theta(1+cos \theta)}

Cancelling the common term of numerator and denominator

=\frac{sin \theta}{cos \theta} = tan \theta

7 0
3 years ago
A= 5 and c = 13 what does b =
Maru [420]
Uh it can really be anything. You should try and be more specific: see if you did the whole problem.
8 0
3 years ago
Read 2 more answers
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