All categories

2 years ago

Please help i will give you a brainlist if you get the right answer

Mathematics

1 answer:

Irina-Kira [14]2 years ago

4 0

You can notice that the shape can be divided into two parts: semi circle and rectangle
the total area=area of semi circle +area of rectangle
area of semi circle =
$\frac{\pi {r}^{2} }{2}$
since the diameter =10 the radius must be 5
area of rectangle is width * height
therefore
area=
$\frac{25\pi}{2} + 20 \times 10 = 239.25$

You might be interested in

At her juice parlor, Mrs. Jones makes a different amount of fruit punch each day by mixing grape juice and peach juice. The tabl

weqwewe [10]

Answer:

Step-by-step explanation:

p and g dont have a difference of 0.6

so it is not b nor c

p is less than g so it is not d

have a nice day and mark me brainliest! :)

8 0

2 years ago

Read 2 more answers

The ratio of catfish to trout in the local pond is 2 to 5. If there are 300 catfish in the pond, how many trout are there?

kumpel [21]

You would do 300/5 since there are 300 catfish

Then multiply the resulting number (60) by 2

The answer is 120

3 0

3 years ago

1.) A 20° sector in a circle has an area of 21.5π yd².

a_sh-v [17]

Part 1) A 20° sector in a circle has an area of 21.5π yd².

What is the area of the circle?

we know that

the area of a circle represent a sector of $360$ degrees

so by proportion

$\frac{21.5\pi }{20} =\frac{x}{360} \\ \\ x*20=360*21.5\pi \\ \\x=(360*21.5*3.14)/20\\ \\x= 1,215.18\ yd^{2}$

therefore

the answer part 1) is

The area of the circle is $1,215.18\ yd^{2}$

Part 2) What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?

we know that

the area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

in this problem we have

$Diameter=21.2\ cm\\ r=Diameter/2\\r=21.2/2\\r= 10.6\ cm$

Find the area of the circle

$A=\pi r^{2}$

$A=\pi*10.6^{2}$

$A=352.8104\ cm^{2}$

Find the area of the sector

we know that the area of the circle represent a sector of $2\pi$ radians

by proportion

$\frac{352.8104}{2\pi }=\frac{x}{(3\pi/5)} \\\\x*2\pi=(3\pi*352.8104)/5\\ \\x= 105.84\ cm^{2}$

therefore

the answer part 2) is

the area of the sector is

$105.84\ cm^{2}$

7 0

3 years ago

Words problems involving length and money

stiv31 [10]

Answer:

Step-by-step explanation:

Since 8 poster takes 48 inches of tape

48/8 = 6

each poster will take 6

if you have two posters

6x2=12

so 12

5 0

2 years ago

Read 2 more answers

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

2 years ago