Answer: figures C and D.
Explanation:
The question is which two figures have the same volume. Hence, you have to calculate the volumes of each figure until you find the two with the same volume.
1) Figure A. It is a slant cone.
Dimensions:
- slant height, l = 6 cm
- height, h: 5 cm
- base area, b: 20 cm²
The volume of a slant cone is the same as the volume of a regular cone if the height and radius of both cones are the same.
Formula: V = (1/3)(base area)(height) = (1/3)b·h
Calculations:
- V = (1/3)×20cm²×5cm = 100/3 cm³
2. Figure B. It is a right cylinder
Dimensions:
- base area, b: 20 cm²
- height, h: 6 cm
Formula: V = (base area)(height) = b·h
Calculations:
- V = 20 cm²· 6cm = 120 cm³
3. Figure C. It is a slant cylinder.
Dimensions:
- base area, b: 20 cm²
- slant height, l: 6 cm
- height, h: 5 cm
The volume of a slant cylinder is the same as the volume of a regular cylinder if the height and radius of both cylinders are the same.
Formula: V = (base area)(height) = b·h
Calculations:
- V = 20cm² · 5cm = 100 cm³
4. Fiigure D. It is a rectangular pyramid.
Dimensions:
- length, l: 6cm
- base area, b: 20 cm²
- height, h: 5 cm
Formula: V = (base area) (height) = b·h
Calculations:
- V = 20 cm² · 5 cm = 100 cm³
→ Now, you have found the two figures with the same volume: figure C and figure D. ←
True these are all equivalent.
Answer:
Check bolded below
Step-by-step explanation:
1)radius = 10 in (given), diameter = 2*radius = 2(10 in) = 20 in
formula for circumference => 2πr => 2π(10)
circumference = 20π in
2)diameter = 12 ft (given), radius = 1/2*diameter = 1/2(12 ft) = 6 ft
formula for circumference => 2πr => 2π(6)
circumference = 12π ft
3)radius = 3 m (given), diameter = 2*radius = 2(3 m) = 6 m
formula for circumference => 2πr => 2π(3)
circumference = 6π m
4)diameter = 18 cm (given), radius = 1/2*diameter = 1/2(18 cm) = 9 cm
formula for circumference => 2πr => 2π(9)
circumference = 18π cm
Answer:
a= 81m^2
Step-by-step explanation:
we know the top triangle: the base is 9
a = 1/2(bh)
a = 1/2 (9 x 8)
a = 1/2 (72)
a = 36
the parallelogram at the bottom has base 9 and height 5
a = bh
a = 9 x 5
a = 45
add them together 36 + 45 = 81
Let h = weight of the hardcover book.
Let p = weight of the paperback book.
<span>"The hardcover version of a book weighs twice as much as its paperback version."
h = 2p
"</span><span>The hardcover book and the paperback together weigh 5.3 pounds.</span><span>"
h + p = 5.3
The equations are:
h = 2p
h + p = 5.3
</span>
