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diamong [38]
3 years ago
14

Given the following functions, evaluate f×g(7)

Mathematics
1 answer:
lidiya [134]3 years ago
3 0

0

evaluate g(7) by substituting x = 7 into g(x

g(7) = (49-35-10)/2 = 4/2 = 2

now substitute x = 2 into f(x)

f(2) = √(4 - 48 + 144) = √0 = 0

(f ○ g)(7) = 0


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What can you conclude from the given information?
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Confused on how to do these Piecewise-Defined evaluations..
Gekata [30.6K]

See the attached image for the graph. The piecewise function is simply a collection of functions glued together to form a sort of "frankenstein function" of sorts. Here's how it works. If x is between 0 and 1 (including 0 but excluding 1), then f(x) = -2 for all x values mentioned. This is exactly what the first row of the piecewise function says. Then the second line says "if x is between 1 and 2, including both endpoints, then f(x) = 3-x". Finally the last line says f(x) = 1 as long as x is larger than 1 but smaller than 4. The value x = 4 is allowed for this piece but x = 1 is not allowed.

--------------------------------------------------

Now onto function evaluation. We want to evaluate f(1) so we need to find f(x) when x = 1. If x = 1, then we'll use the second piece because the first piece excludes x = 1. So

f(x) = 3-x

f(1) = 3-1

f(1) = 2

is the first answer for the function evaluation section.

The value of f(3) is equal to 1 since we resort to using the third piece of the piecewise function (x = 3 is in the range from x = 2 to x = 4)

The value of f(-5) is undefined simply because we're out of the range defined by the piecewise function. The smallest x can get is x = 0.

Finally, f(2) is equal to 1 since...

f(x) = 3-x

f(2) = 3-2

f(2) = 1

again we use the second piece of the piecewise function because x = 2 is in the range 1 <= x <= 2

--------------------------------------------------

In summary:

f(1) = 2

f(3) = 1

f(-5) = undefined

f(2) = 1

Once again have a look at the graph to see how the points match up. I've color-coded the graph so that each piece is a different color. The first piece is in red, the second in blue, the third in green. Note the open hole at point B to indicate "don't include this point as part of the graph".

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