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maria [59]
3 years ago
15

A.8y+4=60 B.4y+8=60C.8÷y+4=60D.y+8+4=60

Mathematics
2 answers:
Gemiola [76]3 years ago
5 0

"<em>The product of 8 and a number increased by 4 is 60" </em>can be written as:

8y + 4 = 60

Your answer is A.

vovikov84 [41]3 years ago
5 0
A is the answer ok fnifnduffhuhfuhfhufuhfuhfuj
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(-2h3n2)(-5h2n2)<br> How
IRINA_888 [86]

Answer: 9h x 8n^2

we rearrange this underneath the question (-5h-2h) (2nx3n)(2+2) or if 2^2 see explanation. It must therefore be 7h6n4

Step-by-step explanation:

if its ^2 )(power2) then the second reasonable answer is (7h-2h)(2n^2 x 2n^2)=9h x 4n^2 x4n^2 =9h 8n^2 or 17hn^2 but i leave as 9h 8n^2

You can expand only if multiplying 9hx4 for example but not combine the letters. The questions that ask you to mix are much different to this. but if you want to add them 9h+8n^2 =17hn^2

3 0
3 years ago
Given cosx=12/13
TiliK225 [7]
1. You have the following information:

 Sinx=5/13

 Cosx=12/13

 2. By definiton, you have:

 Tanx=(Senx)/(Cosx)

 3. When you susbtitute Senx=5/13 and Cosx=12/13 into Tanx=(Senx)/(Cosx), you obtain:

 Tanx=(Senx)/(Cosx)
 Tanx=(5/13)/(12/13)
 Tanx=(5)(13)/(13)(12)
 Tanx=65/156

 4. Therefore, the answer is;

 Tanx=65/156
7 0
3 years ago
How many lines of symmetry does a regular heptagon have?
AfilCa [17]

it has 7 symmetry regular lines



5 0
3 years ago
Read 2 more answers
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
If 32 teams participate in a standard single elimination tournament, how many games must be played to decide a champion?
SCORPION-xisa [38]
<h3>Answer: 31 games</h3>

======================================================

Explanation:

  • 32/2 = 16 games will happen in round 1. Afterward, 16 teams are left.
  • 16/2 = 8 games will happen in round 2. Afterward, 8 teams are left.
  • 8/2 = 4 games happen in round 3.
  • 4/2 = 2 games in round 4.
  • 2/2 = 1 game as the final championship.

Count the number of times you divide by two and we have five occurrences of this. So there five rounds overall.

To get the total number of games played, we add up the quotients

16+8+4+2+1 = 31

----------------

Or as a shortcut we can simply subtract off 1 since 1+2+4+...+2^n = 2^(n+1)-1

We can write that rule as

\displaystyle \sum_{k=1}^{n}2^k = 2^{n+1}-1

which is equivalent to

\displaystyle \sum_{k=1}^{n}2^{k-1} = 2^n-1

3 0
3 years ago
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