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bazaltina [42]
3 years ago
9

You are giving away equal groups of paper clips to some number of friends. Each friend receives 15 paper clips and you started w

ith 90 paper clips. How many friends receive paper clips?
Mathematics
2 answers:
o-na [289]3 years ago
8 0
Well if you divide 90 and 15 you will get 6 and 6 friends got paper clips because 15+15+15+15+15+15... hope this help
Reil [10]3 years ago
3 0
6 friends receive paper clips, because 90 divided by 15 is 6.
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Construct a polynomial function with the following properties: fifth degree, 4 is a zero of multiplicity 3, −4 is the only other
Nonamiya [84]

Answer:

Step-by-step explanation:

Hello,

degree 5

4 is a zero of multiplicity 3 -> (x-4)^3 is a factor

-4 is the only other zero, so the multiplicity is 5-3=2 -> (x+4)^2 is a factor

leading coefficient is 4 so we can write

\boxed{4(x-4)^3(x+4)^2}

If there is something that you do not understand or you are blocked somewhere let us know what / where.

Thank you.

8 0
3 years ago
2,560 divided by 2 what is the answer
ss7ja [257]

2+2-1 that's three quick maths.


5 0
3 years ago
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A line that includes the point (0,0) has a slope of -9. What is its equation in slope-intercept
ikadub [295]
Y=-9x because y=mx+b is the formula so plug in the slope, m(-9) and the x-intercept, x(0)
3 0
3 years ago
10(4-7) What is the value of =(4-1) ? <br>-10 <br>- 6<br> 6<br> 10​
blagie [28]
Answer 10

This is the formula of an arithmetic sequence.
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a
1
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1
a
1
=
1
and
d
=
3
d
=
3
.
a
n
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1
+
(
3
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(
n
−
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a
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Simplify each term.
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4 0
3 years ago
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
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