Answer:
The correct answer is "qualitative, discrete".
Explanation:
A qualitative or discrete trait is defined as a characteristic that have no intermediate features, and is often the result of genetic alleles at a single locus. For instance, if the form the seeds of pea could be either round or wrinkled, but not with intermediate forms. This is the case of the fly that has white or red eyes, but does not have pink eyes or other colors in between.
Answer:
C. The chance of survival decreases when there is intraspecific competition for resources among surviving yearlings
Explanation:
The survival rate of the offspring of the fish species will decrease as a result of the huge number of eggs produced giving rise to overpopulation. Pressure will be on the limited available resources. As a result of this, Intraspecific competition would occur as members of the same fish species would compete for the limited resources.
Interference and exploitation competition are two types of Intraspecific competition that can reduce the population size of the fish species.
For Interference competition, the dominant and stronger members would secure adequate supply of the limited resources to detriment of the weaker and less dominant ones. This leads to the death of those members that are weak to compete successfully, thereby leading to a reduction in population size.
In exploitation competition, it involves all individual members of the fish species sharing the limited resources equally, while none of them gets an adequate amount. With time, a great size of the population decrease would be noticed when compared to that of Interference competition.
Answer:
Fossils are important evidence for evolution because they show that life on earth was once different from life found on earth today paleontologists can determine the age of fossils using methods like radiometric dating and categorize them to determine the evolutionary relationships between organisms.
Explanation:
The statement is true I learned that in pre schoollol
<span>The culture contains 2*10^8 bacteria before it was exposed to ionizing radiation which kills 99.99% of the bacteria. The number of bacteria left after the radiation would be:
final number= initial number * (100%- radiation kill rate)
</span>final number= 2*10^8<span> *(100%-99.99%)
</span>final number= 2*10^8 *(0.01%)
final number= 2*10^8 * 10^-6
final number= 2*10^(8-6)
final number= 2*10^2
