Answer:
The time of a commercial airplane is 280 minutes
Step-by-step explanation:
Let
x -----> the speed of a commercial airplane
y ----> the speed of a jet plane
t -----> the time that a jet airplane takes from Vancouver to Regina
we know that
The speed is equal to divide the distance by the time
y=2x ----> equation A
<u><em>The speed of a commercial airplane is equal to</em></u>
x=1,730/(t+140) ----> equation B
<u><em>The speed of a jet airplane is equal to</em></u>
y=1,730/t -----> equation C
substitute equation B and equation C in equation A
1,730/t=2(1,730/(t+140))
Solve for t
1/t=(2/(t+140))
t+140=2t
2t-t=140
t=140 minutes
therefore
The time of a commercial airplane is
t+140=140+140=280 minutes
Answer:
725 x 10 6th power
Step-by-step explanation:
The number is 725 and there is 6 zero which is converted into the 6th power
Answer:
y=-2x+21
Step-by-step explanation:
use y2-y1/x2-x1 to find the slope so= -17-3/19-9=-20/10=-2
so once you find the slope take one of the points and plug it into the slope-int equation so... if you take (9,3) and take your slope (-2) so it would be: 3=-2(9)+b solve for b to get 21=b as your int. so.. y=-2x+21
