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zysi [14]
3 years ago
6

Is 10/25 and 40/100 equal to 2/5

Mathematics
2 answers:
ad-work [718]3 years ago
6 0
10/25 can be reduced to 2/5 by dividing both the numerator and denominator by 5. 40/100 can also be reduced to 2/5 by dividing both the numerator and denominator by 20. 
yes
forsale [732]3 years ago
5 0
Yes, they are all equal to each other
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x²=100

x²=10×10

x=10

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Malia buys 2 loaves of bread priced at $2.46 per loaf and 2 pound of cheese priced at
aleksandrvk [35]
She spent $19.88 on cheese and bread
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2 years ago
What are axioms in algebra called in geometry?<br> What are axioms in algebra called in geometry
umka21 [38]

Answer:

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5 0
3 years ago
Wilma and Fred rode their bikes toward each other from points on a straight road 32 miles apart. If Fred rode 3 miles per hour f
Firdavs [7]

Answer:

wilma is 22.5 mph

fred is 25.5 mph

Step-by-step explanation:

Time:40 minutes, or 2/3 hours

Speed:

Fred:x+3

Wilma: x

Distance:32 miles

2/3(x+x+3)=32

2/3(2x+3)=32

1 1/3x+2=32

4/3x=30

x=22.5

wilma is 22.5 mph

fred is 22.5+3= 25.5 mph

6 0
3 years ago
A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

\implies 12w -\frac{12}{w^2}=0

\implies 12w^3 - 12=0

w^3-1=0\implies w = 1

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0
3 years ago
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