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4 years ago

A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver

Mathematics

1 answer:

Romashka [77]4 years ago

6 0

Answer:

The time of a commercial airplane is 280 minutes

Step-by-step explanation:

Let

x -----> the speed of a commercial airplane

y ----> the speed of a jet plane

t -----> the time that a jet airplane takes from Vancouver to Regina

we know that

The speed is equal to divide the distance by the time

y=2x ----> equation A

The speed of a commercial airplane is equal to

x=1,730/(t+140) ----> equation B

The speed of a jet airplane is equal to

y=1,730/t -----> equation C

substitute equation B and equation C in equation A

1,730/t=2(1,730/(t+140))

Solve for t

1/t=(2/(t+140))

t+140=2t

2t-t=140

t=140 minutes

therefore

The time of a commercial airplane is

t+140=140+140=280 minutes

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