All categories

3 years ago

What is the sum of the measures of the interior angles of an octagon?

2 answers:

5 0

ANY n-sided polygon has interior angles that sum to 180(n - 2) degrees. For an octagon this is 180 x 6 ie 1080 degrees (so the individual interior angles of a regular octagon are 135 degrees).

irina [24]3 years ago

4 0

Answer:

This is the correct answer and here is why

Step-by-step explanation:

An octagon had 8 Sides (The sides of the polygon is N)

You use the formula:

I=(n *number of sides* - 2) = 180*

I=(8-2)180

I=(6)180

6x180= 1080

N=1080

Therefore the Sum of the measures of the Interior angles of an octagon is: 1080

You might be interested in

Which table correctly shows all the sample spaces for tossing a coin and rolling an odd number on a six-sided number cube? Coin

Sati [7]

Table D I believe :) Hope this helps!!

5 0

3 years ago

Read 2 more answers

PLEASE HELP IM DESPERATE WILL GIVE BRAINLIEST ONLY ANSWER IF YOU ARE HELPING

VARVARA [1.3K]

Answer:

Step-by-step explanation:

u • w

= (i + 6j ) • (9i - 2j )

= (1 × 9 ) + (6 × - 2 )

= 9 + (- 12)

= 9 - 12

= - 3

v • w

= (5i - 3j ) • (9i - 2j )

= (5 × 9) + (- 3 × - 2)

= 45 + 6

= 51

Then

u • w + v • w

= - 3 + 51

= 48

7 0

3 years ago

Each side of a hexagon is 10 inches longer than the previous side. what is the length of the shortest side of this hexagon if it

MrRa [10]

The length of the shortest side of the hexagon is; 41.833 inches

<h3>How to find the perimeter of a Polygon?</h3>

Let the length of the shortest side of the hexagon be x. Now, a hexagon has six sides and if the next side is 10 inches longer than the previous side, then the length of the six sides are;

x, x + 10, x + 20, x + 30, x + 40, x + 50

Perimeter is given as 401 inches. Thus;

x + x + 10 + x + 20 + x + 30 + x + 40 + x + 50 = 401

6x + 150 = 401

6x = 401 - 150

6x = 251

x = 251/6

x = 41.833 inches

Read more about Polygon Perimeter at; brainly.com/question/14490532

#SPJ1

3 0

2 years ago

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=77°, and CD = 41 feet. Find the length of BC to the nearest foot.

OLga [1]

Answer:

182 ft

Step-by-step explanation:

When you are not given a diagram, always draw one for yourself (see diagram).

When you have a right triangle (triangle with 90° angle), you can use the trigonometry ratios, You can remember them using SohCahToa. It is read like this:

sinθ = opposite/hypotenuse Soh

cosθ = adjacent/hypotenuse Cah

tanθ = opposite/adjacent Toa

"θ" means the angle of reference (the angle you are talking about).

We are looking for the length of BC, which is the hypotenuse. I labelled it "d" (lowercase D) because it is opposite to ∠D.

We know ∠C = 77°. This will be our angle of reference (replace θ).

The side we know is DC, also known as "b" (lowercase B) because it's opposite to ∠B. "b" is the adjacent side when θ = C because "b" is touching ∠C.

Take the general trig. formula that has hypotenuse and adjacent: (cosine ratio)

cosθ = adjacent/hypotenuse

Substitute the variables specific for this problem.

cosC = b/d

Substitute the values you know.

cos77° = (41 ft) / d

Isolate "d" to the left side

dcos77° = $d*\frac{41ft}{d}$ Multiply both sides by "d"

dcos77° = 41 ft

dcos77° / cos77° = 41 ft / cos77° Divide both sides by cos77°

d = 41 ft / cos77° Input into calculator

d = 182.261874....... ft Unrounded answer

d ≈ 182 ft Rounded to nearest foot (whole number)

Remember d = BC. It's often easier to use one letter for calculations.

Therefore the length of BC is about 182 feet.

8 0

3 years ago

(there both the same problem) I don't understand this problem may i pleas get help?

Jlenok [28]

Are wee getting the outline size? or what?

7 0

2 years ago