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Ksenya-84 [330]
3 years ago
10

I need help? Can somebody explain to me what you do here and give me the answer? Please and Thank You

Mathematics
1 answer:
rjkz [21]3 years ago
7 0

Answer:

you just locate where those fractions, decimals and percentage are located..

it's better if you turn them into decimal so it's easier to locate..

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Have you ever been on or seen a ride like this at a fair or amusement park? Imagine being strapped into your seat at the bottom
Montano1993 [528]

Answer:

  no

Step-by-step explanation:

The only question here seems to be ...

  Have you ever been on or seen a ride like this at a fair or amusement park?

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How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
PLEASE HURRYY I GIVE BRAINLIEST!!!
Illusion [34]

Answer:

16x+9

Hope this helps:)

8 0
3 years ago
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