All categories

3 years ago

On Saturday, 90 people visited a museum, Tickets to the museum cost

Mathematics

1 answer:

AveGali [126]3 years ago

3 0

Answer:

64 adult tickets were sold

Step-by-step explanation:

Let a = adult tickets sold

c = child tickets sold

a+c = 90 since there were 90 tickets sold

12a+7c = 950 since the amount of money collect is 950

c = 90-a

Substitute this into the second equation

12a +7( 90-a) = 950

Distribute

12a + 630-7a = 950

Combine like terms

5a +630 = 950

Subtract 630 from each side

5a = 950-630

5a = 320

Divide by 5

5a/5 = 320/5

a =64

64 adult tickets were sold

You might be interested in

The second new path will increase access to the gazebo. It will be perpendicular to the the existing path and pass through g (7,

Novosadov [1.4K]

Answer:

C. y = 1/4x + 1/4

Step-by-step explanation:

Just did it on Edmentum and got it right

8 0

3 years ago

Find the 22nd term of the arithmetic sequence whose common difference is d=4 and whose first term is a, = 3

gayaneshka [121]

Answer:

Step-by-step explanation:

t22 = a + (n- 1)d

t22 = 3 + 21*4

t22 = 3 + 84

t22 = 87

3 0

3 years ago

The sum of two numbers is 41. The larger number is one less than twice the smaller number. Find the numbers.

Arte-miy333 [17]

I hope this helps you

small a

larger 2a-1

a+2a-1=41

3a=42

a=14

2a-1=2.14-1=27

6 0

4 years ago

Wht is the volume of 729 cubed feet

lorasvet [3.4K]

Answer:

118085.765 hope this helps have a nice day please give me brainliest:)

Step-by-step explanation:

5 0

3 years ago

In △ABC , line AB is extended up to point E and line BC is extended up to D . The measure of some of the angles is given as; ∠BA

Over [174]

Answer:

$\angle ACD = 130 ^\circ$ .

Step-by-step explanation:

$\angle ABC$ and $\angle EBC$ are supplementary angles. Their sum should be $180^\circ$ . $\angle EBC = 120^\circ$ $\implies \angle ABC = 180^\circ - \angle EBC = 180^\circ - 120^\circ = 60^\circ$ .

The sum of the three angles in triangle $\triangle ABC$ : $(\angle ABC + \angle BAC + \angle ACB)$ should be equal to $180^\circ$ .

$\angle ABC = 60^\circ$ and $\angle BAC = 70^\circ$ $\implies \angle ACB = 180^\circ - \angle ABC - \angle ACB = 180^\circ - 70^\circ - 60^\circ = 50^\circ$ .

$\angle ACB$ and $\angle ACD$ form another pair of supplementary angles. Their sum should also be $180^\circ$ . $\angle ACB = 50^\circ$ $\implies \angle ACD = 180^\circ - \angle ACB = 180^\circ - 50^\circ = 130^\circ$ .

8 0

4 years ago