The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
#SPJ1
Answer:
C
Step-by-step explanation:
3 1/2 x 2 = 7
let x represent granddaughter and x +2 for grandson and together they = 12
so then we have the equation of x+2+x = 12
combine like terms 2x +2 =12
-2 from both sides to isolate x
2x=10 divide both sides by 2 to get x by itself
so we get x = 5 then add 2 +5=7
so grandson is 7 and granddaughter is 5
Answer:
x = 53
Step-by-step explanation:
The sum of the exterior angles of a convex polygon is always 360°.
x +x +59 +48 +50 +39 +58 = 360
2x +254 = 360 . . . . simplify
x +127 = 180 . . . . . . divide by 2
x = 53 . . . . . . . . . . . subtract 127
42.56 hope I helped :)
x10
---------
425.6
