Answer:
yes
Step-by-step explanation:
because side a (4) and side b (5) added together are greater or equal to side c (8)
Answer:
<u>SSS</u>
Step-by-step explanation:
it means side side side and the lines represent their congruecny with the other triangle, meaning that the two line dash is equal to the other two line dash and the one line dash is equal to the other one line dash and you know the last side is the same with eachother because they are sharing that side of the triange
hope it helps have a great day
im not having a great day i got 101 notifications. guess what they were. A MODERATOR DELETED <u><em>ALL</em></u> MY ANSWERS AND NOW I HAD TO START OVER I HAD 23 BRAINLIESTS AND 2983 POINTS AND NOW I HAVE -76 POINTS
Answer:






Step-by-step explanation:
Given

See attachment for proper table
Required
Complete the table
Experimental probability is calculated as:

We use the above formula when the frequency is known.
For result of roll 2, 4 and 6
The frequencies are 13, 29 and 6, respectively
So, we have:



When the frequency is to be calculated, we use:


For result of roll 3 and 5
The probabilities are 0.144 and 0.296, respectively
So, we have:


For roll of 1 where the frequency and the probability are not known, we use:

So:
Frequency(1) added to others must equal 125
This gives:


Collect like terms


The probability is then calculated as:


So, the complete table is:






Answer:
6 F
Step-by-step explanation:
We want to find the temperature difference
Given that the initial temperature read minus 17 F
And the new temperature is increased by 23 F
The new temperature is
=-17+23= 6 F
Therefore the new temperature is 6F