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nadezda [96]
3 years ago
5

3x^2+15x+25=−3x−2whats the discrimate?​

Mathematics
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer:

The discriminate is 0

Step-by-step explanation:

Hope this helps!

Vaselesa [24]3 years ago
4 0

Answer:

- 315

Step-by-step explanation:

Given a quadratic equation in standard form ax² + bx + c : a ≠ 0

Then the discriminant is

Δ = b² - 4ac

Given

3x² + 15x + 25 = - 3x - 2 ( subtract - 3x - 2 to both sides )

3x² + 18x + 27 = 0 ← in standard form

with a = 3, b = 18 and c = 27, then

b² - 4ac = 3² - (4 × 3 × 27) = 9 - 324 = - 315

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25^9+5^17 is divisible by 30.
miskamm [114]

Answer:

1.5 x 10↑11

Hopefully that helps.

8 0
3 years ago
Stacy earns a salary of 2,500. She also receives a 8% commission on any sales that she makes that month. If she makes a total of
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Rewrite sin^4xtan^2x in terms of the first power of the cosine
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3 years ago
Brianna's teacher asks her if these two expressions 3r +5 and 4r are equivalent.
sukhopar [10]

Answer:

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Have a good day fellow lad,

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4 0
2 years ago
Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

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Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
3 years ago
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