Question

M is the midpoint of jk. find the y coordinate of k if j(-8,4) and m(-3,2)

Answer 1

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ j(\stackrel{x_1}{-8}~,~\stackrel{y_1}{4})\qquad k(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x-8}{2}~~,~~\cfrac{y+4}{2} \right)~~=~~\stackrel{m}{(-3,2)}\implies \begin{cases} \cfrac{x-8}{2}=-3\\[0.8em] x-8=-6\\ \boxed{x=2}\\[-0.5em] \hrulefill\\ \cfrac{y+4}{2}=2\\[0.8em] y+4=4\\ \boxed{y=0} \end{cases}$