Using the chain rule: The derivative of e^u is (e^u)(u'). Notice that e^u is rewritten exactly as is and then multiplied by the derivative of the exponent.
Let u=2x. So u'=2
So the derivative of e^u is e^(2x)*2 This can also be written as 2e^(2x).
The complete question asks "If mDB <span>= 60° and PE = 3, then PB =?"
The correct answer is
C) PB = 6.
Explanation:
See the attached picture for reference.
We know
</span>∠DBP = 60°
PB ≡ PD because they are both radius of the circunference, which means that ΔPDB is an isosceles triangle of base DB.
As a consequence, ∠DBP ≡ <span>∠PDB = 60°.
But then </span>∠DPB = 180 - 60 - 60 = 60°.
An isosceles triangles with all the angles measuring 60° is an equilateral triangle.
In an equilateral triangle, the height (DE) cuts into to equl parts the side PB, which means that PE = (1/2) PB
We know PE = 3, therefore
PB = 2 × PE
= 2 × 3
= 6
Hence,
PB = 6.
Answer:
h(t) = –5t + 500
Step-by-step explanation:
Answer: 19.21
Step-by-step explanation:
12^2 + b^2 = 15^2
subtract 12^2 from both sides
b^2 = 15^2 - 12^2
b^2 = 81
b = 9
credit to melissanix90 for helping
Hope this helps :)