Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
If your average speed is 2.05 and your time is the average of .87+.94+.72=0.843 then your answer should be 1.728 because distance= speed x time. I don’t know if this is correct because you didn’t label what the numbers were but I hope this helped you!! :)
Answer:
evaluate the function with -3 as x value
Step-by-step explanation:
4(-3) + 5
-12 + 5
= -7
70/81 is 7/81+7/9 as a proper fraction