The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.
<h3>How to calculate the radius?</h3>
From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.
Let A = area of the triangle
Let S = semi perimeter of the triangle.
The radius will be: = A/S
where,

The radius will be:

= 3.33cm
In conclusion, the radius is 3.33cm.
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ABCD is a parallelogram Given
AE=CE, BE=DE <span>The diagonals of a parallelogram are bisect each other
</span>∠AEB=∠CED Vertical angles are congruent
ΔABE is congruent to ΔCDE SAS theorem<span>
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It's two. 50% chance of heads, 50% chance of tails.
5 times 2/6 is 10/6
You can simplify that to 5/3