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Zarrin [17]
3 years ago
7

Plz find me the k and I will thank u

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0
(5/6)k=-10

K=(6/5)*-10
K=-60/5
K=-12
-12
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We do not have students using Brainly anymore and don't want to be charged for its use. How do we quit being charged?
Varvara68 [4.7K]

Answer: go to account settings press subscriptions and beau my should show up and just cancel subscription

Step-by-step explanation:

7 0
3 years ago
The volume of a rectangular prism can be modeled by the expression 4x3 - 108.
balandron [24]

Answer:

4(x - 3)(x^2 + 3x + 9)

Step-by-step explanation:

4x^3 - 108 = 4(x^3 - 27), or

                    4(x^3 - 3^3), or

                     4(x - 3)(x^2 + 3x + 9)    

We could choose to let 4 represent the height of the prism, x - 3 the width and x^2 + 3x + 9 the length.

6 0
3 years ago
By driving 8 mph faster than Bob, John can make a 230 mile trip in one half hour less.How fast does Bob drive on the trip? Round
aivan3 [116]

Answer:

  57 mph

Step-by-step explanation:

Let b represent Bob's speed on the trip. Then his time is ...

  time = distance/speed

  Bob's time = 230/b

Then John's speed is b+8, and his time is ...

  John's time = 230/(b+8)

The difference of their times is 1/2 hour:

  Bob's time - John's time = 1/2

  230/b -230/(b+8) = 1/2 . . . substitute the expressions for time

  460(b+8 -b) = b(b+8) . . . . . multiply by 2b(b+8)

  b^2 +8b -3680 = 0 . . . . . . .put in standard form

  (b +4)^2 -3696 = 0 . . . . . . . add 16-16 to complete the square

  b = -4 +√3696 ≈ 56.795 . . . solve for positive b

Bob's drove about 57 mph on the trip.

3 0
3 years ago
PROVE THAT:<br><br>cos 20° - sin 20° = ​​ \sqrt{2}sin25°<br><br>​
Lemur [1.5K]

Answer:

See below.

Step-by-step explanation:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

First, use the co-function identity:

\sin(90-x)=\cos(x)

We can turn the second term into cosine:

\sin(20)=\sin(90-70)=\cos(70)

Substitute:

\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Now, use the sum to product formulas. We will use the following:

\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})

Substitute:

\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70)  =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)

Use the even-odd identity:

\sin(-x)=-\sin(x)

Therefore:

\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Replace the second term with the original term:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

Proof complete.

4 0
4 years ago
Need helppppp I’m stuckkkk
Galina-37 [17]

Answer:

b) 94

Step-by-step explanation:

The Total Degree of a Triangle is 180 degrees. Knowing this, set up an equation.

68+26+x=180.

x is the complementary angle of the "?" angle.

Solve the equation.

94+x=180

x=86

Then Subtract 86 from 180 to find "?"

180-86=94

I hope this helps!

6 0
3 years ago
Read 2 more answers
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