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Ganezh [65]
3 years ago
5

I'll give brainliest to whoever shows there work. Plz answer before 2: 30 pm.

Mathematics
2 answers:
irga5000 [103]3 years ago
6 0

Answer:

Its 1,2, and 3.

<3

olchik [2.2K]3 years ago
4 0

Answer:

1st, 3rd and 5th statements are true.

Step-by-step explanation:

We have been given a table that hows the number of cars sold each month for 5 months at two dealerships. We are asked to choose the correct statement from the given choices.

1. The mean number of cars sold in a month is the same at both dealerships.

Let us find mean sales for both dealerships.

\text{Mean}=\frac{\text{Sum of all number of data set}}{\text{Total number in data set}}

\text{Mean sales for Admiral autos}=\frac{4+19+15+10+17}{5}

\text{Mean sales for Admiral autos}=\frac{65}{5}

\text{Mean sales for Admiral autos}=13

\text{Mean sales for Countywide Cars}=\frac{9+17+14+10+15}{5}

\text{Mean sales for Countywide Cars}=\frac{65}{5}

\text{Mean sales for Countywide Cars}=13

We can see that mean number of cars sold at both dealerships, therefore, statement 1st is true.  

2. The median number of cars sold in a month is the same at both dealerships.

Let us arrange our given data set from least to greatest.

Median sales for Admiral autos: 4, 10, 15, 17, 19.

As our data set have 5 data points, therefore, the median will be the value of 3rd data point that is 15.

Median sales for Countywide Cars: 9, 10, 14, 15, 17.

As our data set have 5 data points, therefore, the median will be the value of 3rd data point that is 14.

Since the median number of cars sold at both dealerships is different, therefore, 2nd statement is false.

3. The total number of cars sold is the same at both dealerships.

We have already seen that both dealerships sold 65 cars, therefore, 3rd statement is true.

4. The range of the number of cars sold is the same for both dealerships.

\text{Range}=\text{The highest value- The Lowest value}

\text{Range of Admiral Autos}=19-4

\text{Range of Admiral Autos}=15

\text{Range of Countywide Cars}=17-9

\text{Range of Countywide Cars}=8  

Since the ranges of both dealerships are different, therefore, 4th statement is false.

5. The data for Admiral Autos shows greater variability.


Let us find standard deviation of both data sets.

\sigma=\sqrt{\frac{\sum(x-\overline x)^2 }{n-1}}

\text{SD of Admiral Autos}=\sqrt{\frac{(4-13)^2+(19-13)^2+(15-13)^2+(10-13)^2+(17-13)^2}{5-1}}

\text{SD of Admiral Autos}=\sqrt{\frac{(-9)^2+(6)^2+(2)^2+(-3)^2+(4)^2}{4}}

\text{SD of Admiral Autos}=\sqrt{\frac{81+36+4+9+16}{4}}

\text{SD of Admiral Autos}=\sqrt{\frac{146}{4}}

\text{SD of Admiral Autos}=\sqrt{36.5}\approx 6.04

\text{SD of Countywide Cars}=\sqrt{\frac{(9-13)^2+(17-13)^2+(14-13)^2+(10-13)^2+(15-13)^2}{5-1}}

\text{SD of Countywide Cars}=\sqrt{\frac{(-4)^2+(4)^2+(1)^2+(-3)^2+(2)^2}{4}}

\text{SD of Countywide Cars}=\sqrt{\frac{16+16+1+9+4}{4}}

\text{SD of Countywide Cars}=\sqrt{\frac{46}{4}}

\text{SD of Countywide Cars}=\sqrt{11.5}\approx 3.39

Since SD for Admiral Autos is 6.04 and SD for Countywide Cars is 3.39, therefore, 5th statement is true indeed.

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sladkih [1.3K]
It’s D, when lines are perpendicular, the slopes of the lines are opposite reciprocals.
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3 years ago
Solve for x. Show your work.<br><br> -1/2 x &lt; -12
lesantik [10]
All you need to do is divide -1/2 onto the other side.

-1/2x<-12

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Also, since you are dividing a negative, you flip the sign.

x>6

I hope this helps!
~cupcake
3 0
2 years ago
Read 2 more answers
Would really appreciate if u could help me with all letters but even a few are great! Thanks (the graph is hard to explain so i
defon
Part A

The equation is b = 36*a or simply b = 36a

We take the size of the farm 'a' and multiply it by 36 to get the number of bushels of corn 'b'.

-----------------------------------

Part B

The 36 means there are 36 times more bushels of corn compared to the size of the farm in acres

For example, if the size is 2 acres then 
b = 36*a
b = 36*2
b = 72
yielding 72 bushels of corn

-----------------------------------

Part C

Along the first row you should have: 25 and 30 in the missing blanks (over 900 and 1080 respectively)

You find this by dividing the value of b over 36
eg: b/36 = 900/36 = 25

-------

Then along the bottom row you should have the following for the blanks: 0, 360, 1800

These values are found by multiplying the 'a' value by 36
eg: if a = 10 then b = 36*a = 36*10 = 360

-----------------------------------

Part D

Plot any two points you want from the table back in part C
So plot say (0,0) and (10,360). Then draw a straight line through those two points.

-----------------------------------

Part E

The point (30,1080) means a = 30 and b = 1080
So if the farm is 30 acres, then it can produce 1080 bushels of corn

Notice how
b = 36*a
b = 36*30 <<-- replace 'a' with 30
b = 180
And how this matches up with the fourth column of the table in part C. So you can use this part to get a hint of how to fill out the table (or at least know what one column looks like)


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2 years ago
Express sin A,cos A and tan A as ratios
OverLord2011 [107]

Answer:

Part A) sin(A)=\frac{2\sqrt{42}}{23}

Part B) cos(A)=\frac{19}{23}

Part C) tan(A)=\frac{2\sqrt{42}}{19}

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

sin(A)=\frac{BC}{AB}

substitute the values

sin(A)=\frac{2\sqrt{42}}{23}

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

so

cos(A)=\frac{AC}{AB}

substitute the values

cos(A)=\frac{19}{23}

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

tan(A)=\frac{BC}{AC}

substitute the values

tan(A)=\frac{2\sqrt{42}}{19}

8 0
2 years ago
Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin
Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

A=0.48

B=0.13

AB=0.03

O=0.36

As we know that when A and B both are independent that

P(A and B)= P(A) X P(B)

The probability that both phenotypes O are in independent:

P(O and O)= P(O) X P(O)

P(O and O)= 0.36 X 0.36 =0.1296

P(O and O) =0.1296

The probability that the phenotypes of two randomly selected individuals match:

Here  four case are possible

So

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

P=0.3778

7 0
2 years ago
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