Answer:
1. 10 bits
2. 1022 Hosts / Subnet
Explanation:
Given Network ID is 172.20.0.0
Class B network contains :
Network ID = 16 bits
Host ID = 16 bits
For subnetting always host id bits are used.
Number of subnets required = 50. Subnets are always in power of two. Nearest power of two to 50 is 26 = 64.
So, to create subnet we require 6 bits from host id and 64 subnets can be created with those 6 bits.
1)
Number of host bits needed for new subnets for network information = 6 bits.
Therefore, New network information contains :
Network ID of subnet = 16 + 6 = 22 bits
Host ID = 16- 6 = 10 bits.
2)
Subnets required = 50
Subnets created with 6 bits = 64.
Number of subnets unused for future expansion = 64 - 50 = 14 subnets.
Host ID part contains 10 bits. Therefore, Total number of Hosts /Subnet = 210 = 1024 Hosts.
Number of usable hosts per subnet = 1024 -2 = 1022 Hosts / Subnet.
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Answer:
The correct answer to the following question will be Option A.
Explanation:
For such a standards-compliant perspective, the WITH CHECK OPTION clause could be provided to prohibit additions to rows under which the select statement WHERE clause is sometimes not valid.
- This also prevents changes to rows under which the WHERE clause becomes accurate but perhaps the change will result in it not being valid.
- It helps to prevent updating of a row throughout a view process if this causes the row to still be omitted from those in the display.
Organization and access method.
Hope this helped! :)
- Jujufire