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slega [8]
3 years ago
6

Factor the Higher degree polynomial 5y^4 + 11y^2 + 2

Mathematics
2 answers:
kotykmax [81]3 years ago
8 0

\bf 5y^4+11y^2+2\implies 5(y^2)^2+11y^2+2\implies (5y^2+1)(y^2+2)

RideAnS [48]3 years ago
5 0

For this case we must factor the following polynomial:

5y ^ 4 + 11y ^ 2 + 2

We rewrite y ^ 4as (y^ 2) ^ 2:

5 (y ^ 2) ^ 2 + 11y ^ 2 + 2

We make a change of variable:

u = y ^ 2

We replace:

5u ^ + 11u + 2

we rewrite the middle term as a sum of two terms whose product of 5 * 2 = 10 and the sum of 11.

So:

5u ^ 2 + (1 + 10) u + 2

We apply distributive property:

5u ^ 2 + u + 10u + 2

We factor the highest common denominator of each group.

(5u ^ 2 + u) + (10u + 2)\\u (5u + 1) +2 (5u + 1)

We factor again:

(u + 2) (5u + 1)

Returning the change:

(y ^ 2 + 2) (5y ^ 2 + 1)

ANswer:

(y ^ 2 + 2) (5y ^ 2 + 1)

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3 years ago
What is 4 3/10 plus (-6.2) in decimal form
k0ka [10]

Answer:

Step-by-step explanation:

First change 4 3/10 to 4.3. Then you change 4.3 + -6.2 to 4.3 - 6.2.

Then you do 4.3 - 6.2 and you should get - 1.9.

5 0
3 years ago
Read 2 more answers
Sixty seven percent of the employees in a company have managerial positions, and 58 percent of the employees in the company have
Kazeer [188]

Answer: The proportion of employees who either have MBAs or are managers are 0.58.

Step-by-step explanation:

Since we have given that

Probability of employees having managerial positions = 67%

Probability of employees having MBA degrees = 58%

Probability of managers having MBA degrees = 67%

So, using probability formulas, we get that

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.67+0.58-0.67\\\\P(A\cup B)=0.58

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7 0
3 years ago
Some Math i can’t helppp
mezya [45]

Annually The amount after 10 years = $ 7247.295

quarterly compound after 10 years = $7393.5

Continuously interest =$7,419

Given:

P = the principal amount

r = rate of interest

t = time in years

n = number of times the amount is compounding.

Principal =  $4500

time= 10 year

Rate = 5%

To find: The amount after 10 years.

The principal amount is, P = $4500

The rate of interest is, r = 5% =5/100 = 0.05.

The time in years is, t = 10.

Using the quarterly compound interest formula:

A = P (1 + r / 4)4 t

A= 4500(1+.05/4)40

A= 4500(4.05/4)40

A= 4500(1.643)

Answer: The amount after 10 years = $7393.5

Using the Annually  compound interest formula:

A = P (1 + r / 100) t

A= 4500(1+5/100)10

A= 4500(105/100)10

Answer: The amount after 10 years = $ 7247.295

Using the Continuously  compound interest formula:

e stands for Napier’s number, which is approximately 2.7183

A=Pex^{rt} \\A=4500(e)^{.5} \\A= 4500(2.71)^{.5}

A= $2,919

Answer: The amount after 10 years = $4500+$2,919=$7,419

More details :brainly.com/question/13307568

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7 0
1 year ago
I need to know how to find the initial value, Rate of Charge, and The equation
MrRa [10]
Use a porportion to help better and speed up the process

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2 years ago
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