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3 years ago

Which best explains why | -4 | = 4

Mathematics

2 answers:

castortr0y [4]3 years ago

7 0

B, because | | means opposite of

Vera_Pavlovna [14]3 years ago

5 0

The answer is A because -4 is 4 units from 0

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Effective Rate find the effective rate of interest corresponding to a nominal rate of 7.5% per year compounded.

Jlenok [28]

Answer:

(A) 7.5 %

(B) 3.75 %

(D) 0.625 %

Step-by-step explanation:

We have given effective rate of interest r = 7.5%

(a) Annual rate of interest will be equal to 7.5 %

(B) As we know that 1 year = 12 months

And interest is compounded semiannually

1 semiannual = 6 months

So semiannual rate of interest will be equal to $\frac{7.5}{2}=3.75$ %

So number of period in an year = 3

So rate of interest quarterly $=\frac{7.5}{3}=2.5$ %

(D) Amount when amount is compounded monthly '

So number of period in an year = 12

So rate of interest $=\frac{7.5}{12}=0.625$ %

3 0

3 years ago

Please help!!! How do you count (-3y^2+5y) (4y+7)??

levacccp [35]

You must distribute each value like this:

$(-3y^2+5y) (4y+7)\\ \\ (-12y^3-21y^2+20y^2+35y)\\ \\ (-12y^3-y^2+35y)$

Hope that helps!

6 0

4 years ago

Anyone want to become friends? Add me on sc queenalyssa_05

soldi70 [24.7K]

Okay i will follow you

4 0

4 years ago

Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20

Naily [24]

Answer:

$\displaystyle y = x^{-\frac{2}{3}}$

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. $\log(pq)=\log p+\log q$

2. $\displaystyle \log_pq=\frac{1}{\log_qp}$

3. $\displaystyle \log p^q=q\log p$

We are given the equation:

$\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }$

Applying the second property:

$\displaystyle \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}$

Substituting:

$\displaystyle \log_{2}(x) = 3\log_{2}(xy)$

Applying the first property:

$\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))$

Operating:

$\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)$

Rearranging:

$\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)$

Simplifying:

$\displaystyle -2\log_{2}(x) =3\log_{2}(y)$

Dividing by 3:

$\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}$

Applying the third property:

$\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)$

Applying inverse logs:

$\boxed{y = x^{-\frac{2}{3}}}$

7 0

3 years ago

STUDY TIP 1

Mandarinka [93]

Answer:

THANK U!

FOR THE TIP.

HAVE A GREAT DAY!

6 0

3 years ago