Answer:
-4 <u>+</u> 2*sqrt(5)
Step-by-step explanation:
2x^2+16x-8=0
Factor out the 2: 2(x^2+8x)-8=0
Add (b/2)^2 = (8/2)^2 = 16
2(x^2+8x+16)-8 = 0 + 2*16
2(x+4)^2=40
(x+4)^2=20
x+4=<u>+</u>sqrt(20)
x=-4<u>+</u>sqrt(20) = -4 <u>+</u> 2*sqrt(5)
When solving a word problem, it is always important to make sure you actually understand what's going on. It helps to spend some time making sure you assign the proper variables to each part of the problem before attempting to solve it.
Answer:
The interquartile range is 12.
Step-by-step explanation:
In a box-and-whisker plot, the left edge of the box is the lower quartile and the right edge of the box is the upper quartile. The line dividing the box is the median. The end of the left whisker shows the minimum value. The end of the right whisker shows the maximum value.
In your question, the lower quartile is 29, the upper quartile is 41, while the median is 32. The minimum value is 10 and the maximum value is 51.
The formula for the interquartile range is as follows:
Interquartile Range = Upper quartile - Lower quartile
In this question, interquartile range = 41 - 29 which equals 12. Hence, the answer is 12.
the answer is B -- no matter the x factor y should be single
