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Yuliya22 [10]
3 years ago
11

Evaluate the algebraic expression 6g - 11 =8

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0
The answer is to G is -2
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Aliana uses beads that are 5/4 Centimeters long she uses three beads altogether how many centimeters of beads will Aliana use fo
Serga [27]

Answer:

Length of beads altogether in the necklace = 3.75 cm

Step-by-step explanation:

Length of the beads used in a necklace = \frac{5}{4} cm

Number of beads used in the necklace = 3

Therefore, length of beads in the necklace = Length of each bead × Number of beads used

= \frac{5}{4}\times 3

= \frac{15}{4}

= 3.75 cm

Length of the beads altogether in the necklace = 3.75 cm

3 0
3 years ago
Lily has a stamp collection .she has 54 more U.S stamps than foreign stamps . she has 652 stamps in all.
NISA [10]

Answer:

foreign stamps = 299

US stamps = 353

Step-by-step explanation:

Let number of foreign stamps be x.

Given she has 54 more U.S stamps than foreign , US stamps = x +54

Total stamps = US + Foreign

652 = x + 54 + x

652 - 54 = 2x

598 = 2x

x = 299

7 0
3 years ago
Type the missing numbers in this sequence:<br> -101, -105,<br> -109,<br> -117
PIT_PIT [208]

Answer:

The answer is - 113 that is the correct answer skipping in three's and the first one is - 97

6 0
2 years ago
Read 2 more answers
A hot air balloon rose from a height of 100 m to 400 m in 3 minutes. What was the balloon’s rate of change?
maria [59]

Answer:

1.666666667 meter per sec^2

Step-by-step explanation:

I feel like this is physic

using acceleration formla Vf-Vi/t

so 400-100/180sec

300/180

1.666666667 meter per sec^2

Hey  im still learning tell me if you feel like im wrong OwO

7 0
3 years ago
The focus of a parabola is located at (0,–2). The directrix of the parabola is represented by y = 2. Which equation represents t
Archy [21]

Answer:

\boxed{x^2=-8y}

Step-by-step explanation:

(a,b)\ is \ the\ focus\\y=k\ is \ the\ directrice\\\\Formula\ to\ use:\ y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\Here: \ a=0,\ b=-2, \ k=2\\\\y=\dfrac{(x-0)^2}{2(-2-2)} +\dfrac{-2+2}{2} \\\\so\ y=-\dfrac{x^2}{8} \\\\or\ x^2=-8y

3 0
3 years ago
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