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3 years ago

Your family orders delivery from a local restaurant

Mathematics

1 answer:

anyanavicka [17]3 years ago

8 0

Answer:

1 person ordered chicken and 5 people ordered steak

Step-by-step explanation:

Since we have equations already given, lets solve to get the answer.

First, substitution

x=6-y

Then, as per the second equation.

14(6-y) + 17y = 99

84-14y + 17y = 99

3y=99-84

3y= 15

y= 15/3

y= 5

Then

x=6-y

x=6-5

x=1

We got 1 chicken and 5 steak orders

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6x + 2y > 48 solve for y

kozerog [31]

Answer:

y > 24 − 3x

Step-by-step explanation:

Step 1: First, you need to factor out the common term 2.

2 (3x + y) > 48

Step 2: Then, you divide both sides by 2.

$3x+y>\frac{42}{2}$

Step 3: Next, you have to simplify $\frac{42}{2}$ into 24.

3x + y > 24

Step 4: Lastly, subtract 3x from both sides and you're done!

y > 24 − 3x

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3 years ago

A ball is released at a height of 8 inches to roll inside a half-cylinder it rolls to a height of 2 inches on the other side of

yuradex [85]

Answer:

C) 1/8 inch

Step-by-step explanation:

We are given the explicit formula

$a_n=2(\frac{1}{4})^{n-1}$ , where n is the term number.

The third climb up would be the third term; this means we replace n with 3:

$a_3=2(\frac{1}{4})^{3-1}\\\\a_3=2(\frac{1}{4})^2=2(\frac{1}{4}\times \frac{1}{4})=2(\frac{1}{16})=\frac{2}{16}=\frac{1}{8}$

6 0

3 years ago

Please help me!!! I NEED HELP!!!! IM SO CONFUSED

Juliette [100K]

The exponent on the P will be 5

8 0

3 years ago

Read 2 more answers

You have 200 dice in a bag. One of the dice has a six on all sides so it will land on a six every time you roll it. The other 19

LiRa [457]

Answer:

Step-by-step explanation:

There are 200 dice out of which 199 are fair

Prob for 6 in one special die = 1 and

Prob for 6 in other die = 1/6

A1- drawing special die and A2 = drawing any other die

A1 and A2 are mutually exclusive and exhaustive

P(A1) = 1/200 and P(A2) = 199/200

B = getting 6

i) Required probability

= P(A1/B) = $\frac{P(A1B)}{P(A1B)+P(A2B)} \\$

P(A1B) = $\frac{1}{200} *1 = \frac{1}{200}$

P(A2B) = $\frac{199}{200}*\frac{1}{6}=\frac{199}{1200}$

P(B) = $\frac{205}{1200} =\frac{41}{240}$

P(A1/B) = $\frac{1/200}{41/240} =\frac{7}{205}$

P(A2/B) = $\frac{199/1200}{41/240} =\frac{199}{205}$

4 0

3 years ago

If f(x)=4x^2-3 and g9x)=x+1, find (f-g)(x)

kiruha [24]

Step-by-step explanation:

(f-g)(x) = f(x) - g(x)

the same applies to all other basic operations (like addition, multiplication, ...).

so,

(f-g)(x) = 4x² - 3 - (x + 1) = 4x² - 3 - x - 1 = 4x² - x - 4

5 0

2 years ago