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olasank [31]
3 years ago
11

Three times the sum of a number and 21 is at most -26

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0
It would be: 3(x + 21) ≤ -26
3x + 21 ≤ -26
3x ≤ -47
x < -47/3

In short, Your Answer would be -47/3 or 15.67

Hope this helps!

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If the diameter of a circle is 12 feet, then the radius of the circle is
zhuklara [117]
The radius is 6 feet. The radius will always be half of whatever the diameter is
5 0
3 years ago
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Judy is looking to buy a textbook. The book normally costs $75.82, but it is on sale for 35% below
Trava [24]

Answer:

$49.28 is the sale cost.

Step-by-step explanation:

0.35 x 75.82 = 26.537

75.82 - 26.537

= 49.283 and round

3 0
2 years ago
In a function, y varies inversely with x. The consistent of variation is 4. Which table could represent the function?
lianna [129]

Answer:

none of the tables shown

Step-by-step explanation:

Inverse variation is

xy = k where k is the constant

xy = 4

in the top table

-2*2 = -4 so it cannot be the first table

In the middle table

-2 * -8 = 16  so it is not the middle table

In the bottom table

-2 *4 = -8 so it is not the bottom table

There must be a table not shown

5 0
3 years ago
If the 13th and 38th terms of an arithmetic sequence are -53 and -128,
love history [14]

9514 1404 393

Answer:

  -2018

Step-by-step explanation:

The n-th term is ...

  an = a1 +d(n -1)

So, the given terms are ...

  -53 = a1 +12d

  -128 = a1 +37d

Subtracting the first from the second gives ...

  (a1 +37d) -(a1 +12d) = (-128) -(-53)

  25d = -75

  d = -3

The 668th term will be ...

  a668 = a1 +d(668 -1) = a1 +667d = (a1 +37d) +630d

  a668 = -128 +630(-3) = -128 -1890 . . . . substitute for a38

  a668 = -2018

7 0
3 years ago
A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti
prohojiy [21]

ANSWER

Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

To proof

let us assume that the fluid should be drained and replaced with pure antifreeze be x .

As given

A radiator contains 10 quarts of fluid, 30% of which is antifreeze.

Now write 30% in the decimal form

= \frac{30}{100}

Now write 60% in the decimal form

= \frac{60}{100}

After  drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )

The quantity of  antifreeze is

= \frac{30\times (10 - x)}{100}

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

than the equation becomes

= x + \frac{30\times ( 10 - x )}{100} = \frac{60\times10}{100}

solyving

100x +300 - 30x = 600

70x = 300

x = \frac{300}{70}

x = 4.28 quarts (approx)

Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

Therefore the option (c.) is correct .

3 0
3 years ago
Read 2 more answers
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