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3 years ago

What is the removable discontinuity

Mathematics

1 answer:

Usimov [2.4K]3 years ago

7 0

Answer: The third answer.

I took the Quiz.

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A shopper bought a 12-pounds bag of orange for 18.72 what is the unit price per

Naddik [55]

I think the answer is $1.56

i hope this helps

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3 years ago

If there are 6 air conditioners in each require 8 pounds of refrigeration how many pounds of refrigeration are needed to fill al

djverab [1.8K]

8 times 6 = 48 so that’s the answer!

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4 years ago

Sofia is comparing celluer plans. Company A charges a flat fee of 59.99 a month and .43 additional minutes. Company B charges 69

Vsevolod [243]

Answer: it will take 125 additional minutes for both costs to be equal.

Step-by-step explanation:

Let a represent the number of additional minutes that it will it take for the two to be the same.

Company A charges a flat fee of 59.99 a month and .43 additional minutes. This means that the total cost of a additional units would be

0.43x + 59.99

Company B charges 69.99 a month and .35 for additional minutes. This means that the total cost of a additional units would be

0.35x + 69.99

For the cost of the two plans to be the same, it means that

0.43x + 59.99 = 0.35x + 69.99

0.43x - 0.35x = 69.99 - 59.99

0.08x = 10

x = 125

5 0

3 years ago

Let's make one thing clear. That thing you see in the mirror is you being garbage.

xenn [34]

Answer:

Nice roast

Step-by-step explanation:

Don’t be mean tho :(

6 0

3 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago