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zhannawk [14.2K]
3 years ago
11

Clayton purchased eight model car kits he paid the same price for each kit he also bought a new air brush to use for $25 in tota

l Clayton spent $145 how much was each model car kit
Mathematics
1 answer:
wel3 years ago
5 0

Answer:

add

Step-by-step explanation:

add

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I need help plz i dont get it and im trying to get my grade up
Ymorist [56]

Answer:

648

Step-by-step explanation:

(25 - 9 + 2)^2 / 3x6

= 108 x 6

= 608

follow BODMAS and you'll get it

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4 0
3 years ago
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What percent of all patients are blood type AB? Round your answer to the nearest tenth of a percent. Type a numerical answer in
Makovka662 [10]
Depends on the type of AB, is it AB positive or AB negative

<span>AB-positive: 3.4 percent
<span>AB-negative: 0.6 percent

if you need both add the percentages together</span></span>
6 0
2 years ago
Hi can someone please help me with this i will give you five stars!!
tino4ka555 [31]

Step-by-step explanation:

Let's look at what we know. We know that...

P=2000

r=0.04 (Change 4% to a decimal)

t=7 (25 years minus 18 years equals 7)

n=1

Since we are compounding each year, we need to use this equation: P(1+\frac{r}{n} )^{nt}

Now just plug the numbers in: (Answer to #1:) 2000(1+\frac{0.04}{1} )^{(1*7)}

This equals 2631.86

When we round, this equals to $2,632. (Answer to #2).

3 0
2 years ago
Write the following phrase as a variable expression. Use x to represent​ "a number".
mojhsa [17]
Sum means add, a number means x, and four means, uh, 4...

x+4. is what you're looking for
3 0
3 years ago
Od<br> 2<br> (<br> 2 7 1-3<br> 1 3 1-2<br> 6:1-6<br> b =<br> d =<br> IDONE
Lena [83]

Answer:

a = \boxed{1},\: b=\boxed{0}\\\\c=\boxed{0},\: d=\boxed{1}

Step-by-step explanation:

  • \begin{bmatrix} 2 & 7\\\\1 & 3\end{bmatrix}\:\begin{bmatrix} -3 & 7\\\\1 & -2\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Multiply both the matrices on left side, we find:

  • \begin{bmatrix} 2(-3)+7(1) & 2(7)+7(-2)\\\\1(-3)+3(1) & 1(7)+3(-2)\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} -6+7 & 14-14\\\\-3+3 & 7-6\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} 1 & 0\\\\0 & 1\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Comparing the corresponding elements of both the matrices on both sides, we find:

  • a = \boxed{1},\: b=\boxed{0},\:c=\boxed{0},\: d=\boxed{1}
7 0
2 years ago
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