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netineya [11]
3 years ago
5

Solve each data for x: (a) a rectangle has (2x + 1) and (x +2) as length and width. Its area is 77 (b.) a triangle has (2x+2) an

d (x+3) as base and height. Its area is 35
Mathematics
1 answer:
Sergio039 [100]3 years ago
7 0
Area of a rectangle: A= Length*width
(2x+1)(x+2)=77
2x^2+4x+x+2=77
2x^2+5x+2=77
2x^2+5x-75=0
(x-5)(2x+15)=0
x=5 or x=-7.5
Length cannot be negative, so x=5 only
the length is 11, the width is 7
Next, let's look at the triangle.
Area of a triangle: A=1/2 of base*height
(1/2)(2x+2)(x+3)=35
2x^2+8x+6=70
2x^2+8x-64=0
x^2+4x-32=0
(x-4)(x+8)=0
x=4
the base is 10, the height is 7
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Answer:

0.7361

Step-by-step explanation:

In this question we have

number to be 10

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We have q = 1-p

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Then the probability of not more than 1 being defective:

P(x=0) + p(x= 1)

(10C0 x 0.1⁰ x 0.9^10-0)+(10C1 x 0.1¹ x 0.9^10-1)

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= 0.3487 + 0.3874

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This is the the required probability and this answers the question.

probability = 10 percent = 0.1

q= 1- 10percent = 90% = 0.9

n = 4

To get the required probabiltiy for this question is

P(not greater than one is defective )=P(x=0)+P(x=1)

= 4C0x(0.1)⁰x(0.9)⁴+4C1x(0.1)¹x(0.9)³

= 0.9477

The required probability is 0.9477

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3 years ago
Under which condition will two lines not have a common solution
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Answer:

Each shows two lines that make up a system of equations. If the graphs of the equations intersect, then there is one solution that is true for both equations. If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.

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Holly and her two best friends go to dinner the total bill is $31.84 they use a coupon for 15% off the total if they split the b
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Masteriza [31]

Answer:

  • See below

Step-by-step explanation:

<u>Given equation:</u>

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<u>Convert this to standard form by completing the square:</u>

  • (x - h)² + (y - k)² = r², where (h, k) - center, r - radius
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