I need help with this
2 answers:
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So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.
Then third card being spades would be 11 / 50
Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49
Fifth card would be 9 / 48.
So the probability of next three cards being spades would be
Hope this helps.
Then third card being spades would be 11 / 50
Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49
Fifth card would be 9 / 48.
So the probability of next three cards being spades would be
Hope this helps.
Answer:
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Step-by-step explanation:
FOIL
(1/2)h*B1+ (1/2)h*B2=A
subtract the B2 term
(1/2)h*B1 = A- (1/2)h*B2
multiply by 2
h*B1 = 2A - h*B2
divide by h
or