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2 years ago

14

I need help with this

2 answers:

Nat2105 [25]2 years ago

4 0

Answer:

angle B is 38°

Step-by-step explanation:

all angles in a triangle has to equal 180°.

So first find the measurement of angle BAD. This is done by subtracting angle of CAD=46° from the total angle CAB=78° to get 32° for angle BAD. So if angle ADB is 110° and angle BAD is 32° which equals (110+32=) 142.

Then take 180 - 142 = 38°

cupoosta [38]2 years ago

4 0

Answer:

38

Step-by-step explanation:

We can see that A is equal to 78. We can also see that CAD is equal to 46. Therefore BAD is equal to 32. Add 32 and 110 together to get 142. Subtract 142 from 180 to get 38.

Hope that this helps!

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2 years ago

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3 years ago

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mamaluj [8]

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2 years ago

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Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

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Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
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$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

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And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

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Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

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From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

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Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0

1 year ago