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Montano1993 [528]
2 years ago
5

Sonja's credit card has an APR of 21%, calculated on the previous monthly

Mathematics
1 answer:
Leya [2.2K]2 years ago
8 0

Answer: D 87%

Step-by-step explanation:

Ap-ex

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I need help with number 7 please, thanks.
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B, that’s easy... Just add them up.
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A map of New York has a scale of 1/2 inch : 5 miles. Cindy knows the
saveliy_v [14]

Answer:

8.5 inches

Step-by-step explanation:

1/2 in = 5 miles

? = 85 miles.

So you would do 85/5 to figure out how many times you have to multiply 5 to get to 85.

85/5= 17

So then you would multiply 17 by 1/2 to get the answer 8.5. So that would b 8.5 inches

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A cook mixes 4 pounds of rice into 5 quarts of boiling water.
professor190 [17]
I think you could times 4 and 5 to get 20
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3 years ago
Read 2 more answers
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
7 + (10 − 4)2 ÷ 4 × 1\8
natta225 [31]
I’m pretty sure the answer is 12

6 0
2 years ago
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