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lord [1]
3 years ago
14

Why did orgo check hos animal cookies before eating any

Mathematics
2 answers:
Strike441 [17]3 years ago
7 0
He wanted to know if the seal HAD been broken
iVinArrow [24]3 years ago
5 0
<span>He wanted to see whether the seal HAD been broken. </span>
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Help with this math question please
kvv77 [185]
First question.

We will build up the 3-dimensional object from the dimensions shown in the view above. In doing this, the object is as shown in figure 1. So, we need to find the volume of this object. Let's cut off this object into two objects, so in doing this we can find the whole volume as the sum of the volume in green plus the volume in red (both are cubes), so:

V_{t} = V_{g}+V_{r} = 8 \times 3 \times 5 + 8 \times 5 \times 8  = 440 ft^{3}

So the answer is G.

Second question

The answer is D. Let's analyze it:

Given that r represents the radius  of the pizza and n the number of slices, so if we substitute r in this equation, then the values for n are:

n =  r^{2}+1

n=2^{2}+1=5
n=4^{2}+1=17
n=5^{2}+1=16
n=8^{2}+1=65
n=10^{2}+1=101

These are the values of n shown in the table above.

6 0
4 years ago
Simplest form 2/5ths
ratelena [41]

Answer:

2/5 is the simplest form. But in decimal form it is 0.4

Step-by-step explanation:

2/5

=2 divided by 5

=0.4

7 0
3 years ago
Read 2 more answers
Please help asap i need this done
V125BC [204]

Answer:

A. a cube that is 1 meter long, 1 meter wide, and 1 meter high

Step-by-step explanation:

A cube's sides are all equal

8 0
2 years ago
[x^2+2y]^3<br> expand it
777dan777 [17]

(a + b) {}^{3}  = a {}^{3}  + 3a {}^{2} b + 3ab {}^{2}  + b {}^{3}  \\  \\ x {}^{6}  + 6x {}^{4} y + 12x {}^{2} y {}^{2}  + 8y {}^{3}

8 0
3 years ago
Read 2 more answers
The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did
Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

P(A \, and \, B)= P(A)\times  P(B\left |  \right A )

From the options, we have;

P(fatigue \left |  \right drug) = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×P(fatigue \left |  \right drug)  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0
3 years ago
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