It looks very blurry man sorry i cant see what you me to answer :(
Solution: We are given an urn contains 1 red chip and 1 white chip.
Now let's consider the first draw.
The probability of drawing red chip 
We know that if the first chip drawn is red, we will put back that chip into the urn with additional two red chips. So if the first chip drawn is red, we will have 3 red chips and 1 white chip in the urn.
Now if we draw another chip from an urn containing 3 red chips and 1 white chip. Then the probability of drawing a red chip is

Now lets combine these two events
The probability of both are red = P(1st draw is red) . P(2nd draw is red)
=(1/2) x (3/4)
=(3/8)
Therefore, the probability of both selections are red is 3/8
Answer:

Step-by-step explanation:
Given

The number line is missing from the question.
So, I will answer the question and also draw the number line to show the product.


To represent this on a number line;
We draw a number line of 15 points, and place a dot on the 6th point.
This represents 6/15
See attachment
1-) isolate the radical symbol on one side of the equation
2-) square both sides of the equation to eliminate the radical symbol