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tigry1 [53]
3 years ago
11

Help me Help me Help me

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

For the first one is 75 and 30 looks on a calculator add 75+75+30=180

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If the mean is 298 and standard deviation is 22 what is the probability that a random sample of 42 pregnancies has a mean gestat
anyanavicka [17]

Answer:

The probability is 0.9909.

Step-by-step explanation:

Test statistic (z) = (sample mean - population mean) ÷ (sd/√n)

sample mean = 290 days

population mean = 298 days

sd = 22 days

n = 42

z = (290 - 298) ÷ (22/√42) = -8 ÷ 3.395 = -2.36

The cumulative area of the test statistic is the probability that the mean gestation period is less than 290 days. The cumulative area is 0.9909. Therefore the probability is 0.9909.

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3 years ago
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Answer:

<u>Geometry</u>

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Step-by-step explanation:

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100 POINTS PLEASE HELP!!!​
solong [7]

Answer:

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Step-by-step explanation:

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2.Solve -75 = -25a.<br> A.<br> 3<br> B.<br> -100<br> c.<br> -50
Step2247 [10]

Answer:

A

Step-by-step explanation:

-75=-25a

Divide both sides by -3:

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