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Yakvenalex [24]
4 years ago
7

Which expression shows (3-4i)+(-7-8i) in simplest form?

Mathematics
1 answer:
expeople1 [14]4 years ago
3 0

Answer:

B)  -4 - 12i

Step-by-step explanation:

(3-4i)+(-7-8i) = 3 -4i - 7 - 8i  

= 3 - 7 - 4i -8i

= -4 - 12i

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What is the volume of the rectangular prism
-Dominant- [34]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help
Harrizon [31]

Answer:

(-1/2, 3/4)

Step-by-step explanation:

Let's use the elimination by adding or subtracting method.  Note that we have 8y in the first equation, and that we could obtain -8y in the second equation by multiplying the second equation by 2:

2(24x - 4y = -15) => 48x - 8y = -30

Now combine this result (this equation) with the first equation:

  2x + 8y = 5

+48x   -8y = -30

---------------------

 50x    =     - 25

Dividing both sides by 50, to isolate x, we get

x = -25/50 = -1/2.

Now substitute -1/2 for x in the first equation and solve the resulting equation for y:

  2x + 8y = 5

2(-1/2) + 8y = 5, or -1 + 8y = 5, or 8y = 6 (after having added 1 to both sides)

Dividing both sides of 8y = 6 by 8 leads to determining the value of y:

y = 6/8 = 3/4

The solution is (-1/2, 3/4).

3 0
3 years ago
Fred flips a coin, spins the spinner, and rolls a standard number cube. Find the probability that the coin will show tails, the
Inessa05 [86]

Answer:

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is \frac{4}{3}  

Step-by-step explanation:

Given : Fred flips a coin, spins the spinner, and rolls a standard number cube.

To find : The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three ?

Solution :

First we find probability one by one,

1) Flips a coin - Head, Tail

Total number of outcome = 2

Favorable outcome (getting a tail) = 1

Probability that the coin will show tails is P(T)=\frac{1}{2}

2) Spins the spinner - yellow, green, blue

Total number of outcome = 3

Favorable outcome (land on yellow or green) = 2

Probability that the spinner will land on yellow or green P(S)=\frac{2}{3}

3) Rolls a standard number cube - 1,2,3,4,5,6

Total number of outcome = 6

Favorable outcome (show a three) = 1

Probability that the cube will show a three P(C)=\frac{1}{6}

The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is

P=P(T)+P(S)+P(C)

P=\frac{1}{2}+\frac{2}{3}+\frac{1}{6}

P=\frac{3+4+1}{6}

P=\frac{8}{6}

P=\frac{4}{3}

Therefore, The probability that the coin will show tails, the spinner will land on yellow or green (out of yellow, green, blue), and the cube will show a three is \frac{4}{3}

5 0
3 years ago
Some one factor 3x^2+7x-20
mylen [45]
Split it up
3x^2+12x-5x-20
group
(3x^2+12x)+(-5x-20)
factor
(3x)(x+4)+(-5)(x+4)
undistribute (x+4) like ab+ac=a(b+c)
(3x-5)(x+4)
6 0
3 years ago
This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

3 0
3 years ago
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