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2 years ago

Does anyone know the answer to this question?

Mathematics

1 answer:

miv72 [106K]2 years ago

3 0

a) means what is the probability of P occurring once Q has occurred. That is 9/24 which is 3/8.

b) is 14/24 which is 7/12.

Please inform me if I gave you the correct answers :)

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Mr.Dow lives 16 miles from his workplace he drives to and from work five days a week if his car gets 19.2 miles per gallon how m

ANEK [815]

Answer:he would require 8.33 gallons of gas

Step-by-step explanation:

Mr Dow lives 16 miles from his workplace he drives to and from work five days a week. It means that the distance that he drives everyday to and from work would be

16 × 2 = 32 miles.

Then, the total distance that he drives in a week to and from work would be

32 × 5 = 160 miles

if his car gets 19.2 miles per gallon, it means that the amount of gas that he would use in one week, commuting to and from work would be

160/19.2 = 8.33 gallons

4 0

3 years ago

Which procedure could be used to graph the following equation ? y=1/4x - 1

aalyn [17]

Answer: A.

Step-by-step explanation:

Plot the y-intercept (0,-1) and use the slope of 1/4 to find a second point

4 0

4 years ago

Read 2 more answers

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago

Solve<br> log4 (x+3)- log4 (x+2)≥3/2<br> Please help

mart [117]

Https://web2.0calc.com/ try this or

this http://rational-equations.com/in-rational-equations/graphing-equations/distributive-property-simplif...
they are math calculator..... hope this helps

4 0

3 years ago

Jerome is on top of a mountain that is 12,060 feet

pochemuha

Answer:

120

Step-by-step explanation:

7 0

2 years ago