Answer:
All the sides of the triangle X'Y'Z' are twice as long as the sides of the original triangle XYZ. The triangle XYZ has been enlarged by a scale factor of 2.
All the sides of the triangle X'Y'Z' are twice as long as the sides of the original triangle XYZ. The triangle XYZ has been enlarged by a scale factor of 2.Enlargement is an example of a transformation. A transformation is a way of changing the size or position of a shape.
All the sides of the triangle X'Y'Z' are twice as long as the sides of the original triangle XYZ. The triangle XYZ has been enlarged by a scale factor of 2.Enlargement is an example of a transformation. A transformation is a way of changing the size or position of a shape.To enlarge a shape, a centre of enlargement is required. When a shape is enlarged from a centre of enlargement, the distances from the centre to each point are multiplied by the scale factor.
All the sides of the triangle X'Y'Z' are twice as long as the sides of the original triangle XYZ. The triangle XYZ has been enlarged by a scale factor of 2.Enlargement is an example of a transformation. A transformation is a way of changing the size or position of a shape.To enlarge a shape, a centre of enlargement is required. When a shape is enlarged from a centre of enlargement, the distances from the centre to each point are multiplied by the scale factor.The lengths in triangle A'B'C' are three times as long as triangle ABC. The distance from O to triangle A'B'C' is three times the distance from O to ABC.
Answer:
1. sum of term = 465
2. nth term of the AP = 30n - 10
Step-by-step explanation:
1. The sum of all natural number from 1 to 30 can be computed as follows. The first term a = 1 and the common difference d = 1 . Therefore
sum of term = n/2(a + l)
where
a = 1
l = last term = 30
n = number of term
sum of term = 30/2(1 + 30)
sum of term = 15(31)
sum of term = 465
2.The nth term of the sequence can be gotten below. The sequence is 20, 50, 80 ......
The first term which is a is equals to 20. The common difference is 50 - 20 or 80 - 50 = 30. Therefore;
a = 20
d = 30
nth term of an AP = a + (n - 1)d
nth term of an AP = 20 + (n - 1)30
nth term of an AP = 20 + 30n - 30
nth term of the AP = 30n - 10
The nth term formula can be used to find the next term progressively. where n = number of term
The sequence will be 20, 50, 80, 110, 140, 170, 200..............
Answer:
34, 20, 35, ...
Step-by-step explanation:
From what I see, it is alternating between two patterns: +5 starting at 5, and +1 starting at 31.
This is really a long way to go to make something complicated
out of something simple. The last choice does the job.
cos(180) = -1
sin(180) = 0
So 4 [cos(180) + i sin(180) ]
= 4 [ -1 + i (0) ]
= -4 yay!
Answer:
There are many. Two examples are
Step-by-step explanation:
There are many examples. The simplest is
1 -
It is trivial that
2 -
That function is injective as well.
An example of a function that is NOT injective is
Notice that
