james recently installed a new pool in his backyard the pool is 20 ft long 15 feet wide and 5 ft deep, what is the volume

Erin feeds her dog 7/10 cup of food a day . With 3/10 cup canned and the rest dry . She also gives her dog 1 treat a day . How m

gavmur [86]

Answer:

$2\frac{4}{5}\ \ or \ 2.8 \ \ cups$

Step-by-step explanation:

-The total portion fed to the dog is 7/10 cup

Canned-3/10
Dry=7/10-3/10=4/10

-One week has 7 days. we multiply the dry portion per day by the number of days in a week.

$Dry= Total -Canned\\\\=\frac{7}{10}-\frac{3}{10}\\\\=0.40 \ cup\\\\Dry \ per \ Week= Dry/ day\times days\\\\=0.40\times 7\\\\=2\frac{4}{5}\ or\ 2.8 \ cups$

Hence, Erin feed her dog 2 4/5 0r 2.8 cups of dry food

5 0

3 years ago

ou are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on cons

PolarNik [594]

Answer:

$(\frac{4\sigma}{2.056})^2$ , rounded up, if needed, citizens should be included in the sample, in which $\sigma$ is the standard deviation of the population.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.056.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Within 4 years of the actual mean

We have to find n for which M = 4. So

$M = z\frac{\sigma}{\sqrt{n}}$

$4 = 2.056\frac{\sigma}{\sqrt{n}}$

$2.056\sqrt{n} = 4\sigma$

$\sqrt{n} = \frac{4\sigma}{2.056}$

$(\sqrt{n})^2 = (\frac{4\sigma}{2.056})^2$

$n = (\frac{4\sigma}{2.056})^2$

$(\frac{4\sigma}{2.056})^2$ , rounded up, if needed, citizens should be included in the sample, in which $\sigma$ is the standard deviation of the population.

8 0

3 years ago

1. Identify the lateral area and surface area of a regular square pyramid with base edge length 5 in. and slant height 9 in.

zlopas [31]

1. C
L=1/2(Pxl)
L=1/2(20x9)
L=1/2(180)
L=90

SA=1/2(Pxl)+B
SA=90+5^2
SA=115

B, A, C, B.

6 0

3 years ago

13. Translate the following verbal phrase

Artyom0805 [142]

a) algebraic expression

$\frac{3+x}{5}=10$