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KonstantinChe [14]
3 years ago
13

The dean of the engineering school at a technical university wants to emphasize the importance of having students who are gifted

at reading and writing as well as math. She wants to know if she can accurately claim that graduate students in engineering programs at her school have significantly higher scores on the verbal reasoning section of the GRE (a standardized test used in the admissions process for many graduate programs) than the national average for engineering students. The national average for the verbal reasoning GRE score for engineering students was 150 with a standard deviation of 9. A random sample of 49 engineering graduate students at her school were found to have an average verbal reasoning GRE score of 153. After analyzing the data to determine whether the mean verbal reasoning GRE score of the engineering graduate students at the technical university is higher than the national average, the p-value of 0.0099 was obtained. Using a 0.05 significance level, what conclusion can be drawn from the data?
Mathematics
1 answer:
larisa [96]3 years ago
8 0

Answer:

Step-by-step explanation:

The null hypothesis: Mean verbal reasoning GRE score of the engineering graduate students at the technical university is less than or equal to the national average: u ≤ 150

The alternative hypothesis: Mean verbal reasoning GRE score of the engineering graduate students at the technical university is greater than the national average: u > 150

Since the p-value of 0.0099 was gotten which is less than the significance level of 0.05, we reject the null hypothesis and conclude that actually there is a statistically significant evidence to prove that the mean verbal reasoning GRE score of the engineering graduate students at the technical university is greater than the national average

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Melanie L. asked • 03/08/16

a pole that is 3.3m tall casts a shadow that is 1.78m long. at the same time, a nearby building casts a shoadow that is 49.75 m long. how tall is the building?

a pole that is 3.3m tall casts a shadow that is 1.78m long. at the same time, a nearby building casts a shoadow that is 49.75 m long. how tall is the building? Round to the nearest meter.

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Jane C. answered • 03/08/16

TUTOR New to Wyzant

Proficient, Efficient, Sincere Elementary and Middle School Math Tutor

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Hi Melanie!

This problem involves proportion.

Let x be the unknown, which is the height of the building.

height of pole = height of the building

height of the shadow height of the shadow

3.3 m = x

1.78 m 49. 75 m

Solve for x.

(3.3 m) (49.75 m) = x

1.78 m

92.2331460674 = x

Rounded to the nearest meter, the building is 92 meters high.

Hope that helps.

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Step-by-step explanation:

Well first let’s covert the ft to in- 5ft is 60 in and 6ft is 72 in. Then we want to set up 2 fractions based on height and shadow, so we have 60/15=x/72 (we put x because that’s what we’re trying to find). Then we do cross multiplication so now we have 15x=4320. We divide 15, so now we have 4320/15=288. So the building is 288 in tall or 24ft tall! Glad to help! :)

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