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Stolb23 [73]
3 years ago
9

Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

Mathematics
2 answers:
BigorU [14]3 years ago
7 0
For a moment, let y=x^2-2x+5. Then by the distributive property,

(2x^2+4x-3)p=2x^2p+4xp-3p


Again by the distributive property,

2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2

4xp=4x(x^2-2x+5)=4x^3-8x^2+20x

-3p=-3(x^2-2x+5)=-3x^2+6x-15

Taking everything together, we get

(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)
(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15
eduard3 years ago
4 0

Answer:

the answer is C

Step-by-step explanation:

got it right on the assignment

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Original Equation:8 - 7x^2 + 3 = 4x^2 - 1Frist step:11 - 7x^2 = -4x^2 - 1Which property justifies the first step?A. Division pro
Tpy6a [65]

8 - 7x^2 + 3 = 4x^2 - 1

8+3-7x^2 = 4x^2-1

11-7x^2 = 4x^2-1

B. Commutative property of addition

We can swap numbers and obtain the same results.

In this case, we swapped 8+3 and added them.

7 0
1 year ago
3/11 divided by 3/11
vladimir2022 [97]

Answer: 1

Step-by-step explanation:

When dividing fractions, we follow a rule called keep, change, flip:

3/11 * 11/3

33/33

1

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!! TRIG, Theres a picture!!
BartSMP [9]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

3(  { \tan }^{2} \theta -    { \sec }^{2}  \theta)

Using trigonometric identities

That's

1 + { \tan }^{2} \theta  =   { \sec }^{2}  \theta

Rewrite the expression

That's

3({ \tan }^{2} \theta - (1 + { \tan }^{2} \theta)) \\

Simplify

We have

3({ \tan }^{2} \theta - 1 - { \tan }^{2} \theta) \\ 3({ \tan }^{2} \theta - { \tan }^{2} \theta - 1)

So we have

3( - 1)

We have the final answer as

<h2>- 3</h2>

Hope this helps you

3 0
3 years ago
Plz help duke for 10 points
BaLLatris [955]

Answer

A) 2(4+5)

2(9)

18

B) 2(10+2)

2(12)

24

C) 4*5

20

D) 10*2

20

7 0
3 years ago
Determine if each set of ordered pairs represents a function
Nostrana [21]
Where is the picture?
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3 years ago
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