Let l and l-6 be the length and width, respectively, of the rectangle. Then:
l(l-6)=40
l²-6l-40=0
(l-10)(l+4)=0
l=10,-4
The rectangle is 10" by 4". ☺☺☺☺
The opposite angles equal each other, so X and Z are equal
using that we solve for x by setting them equal:
6x-60 = 2x+68
subtract 2x from each side:
4x -60 = 68
add 60 to each side:
4x = 128
divide both sides by 4
x = 128/4
x = 32
now we know x so we can solve everything else by replacing x with 32
WY = 3x+5 = 3(32)+5 = 96+5 = 101
angle Z = 2x+68 = 2(32)+68 = 64+132
the answer is C
Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0
Discriminant = 4 - 4(K)(-1) = 4 + 4K
For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.
The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.
I would say 6 hours but i don’t think it is, sorry this one is a real tricky one
Answer:
a graph can be divided into 4 quadrants.
a zero abscissa, means the point lies on the origin.
a negative ordinate means the point lies on the y axis in the third and fourth quadrants.
