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Dovator [93]
4 years ago
14

Cody is jogging at a constant speed of 4 mph which graph could represent his jog

Mathematics
1 answer:
polet [3.4K]4 years ago
8 0
The first one, the level line. because it is a constant rate and not fluctuating 
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What are the values of a, b and c in the quadratic equation -2x^2+4x-3=0?
AlladinOne [14]

Answer:

a=-2\\b=4\\c=-3

Step-by-step explanation:

In a quadratic equation in the Standard form

ax^2+bx+c=0

You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: a\neq0).

You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:

-2x^2+4x-3=0

Therefore, you can identify that the values of "a", "b" and "c" are the following:

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How many pounds are equivalent to 40 oz​
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Answer:

Step-by-step explanation:

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3 years ago
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Can someone help me plsss
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100 = 36 + x^2

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3 years ago
A research group is curious about their city’s participation in flu shot clinics. They suspect that there is a difference betwee
Kipish [7]

Answer:

t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505  

p_v =2*P(t_{40}>0.505)=0.61633  

Comparing the p value with the significance level \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.  

Step-by-step explanation:

Data given and notation

\bar X_{1}=162 represent the mean for sample of clinic attendees

\bar X_{2}=156 represent the mean for the sister city  

s_{1}=41 represent the sample standard deviation for 1  

s_{2}=36 represent the sample standard deviation for 2  

n_{1}=22 sample size for the group 2  

n_{2}=20 sample size for the group 2  

\alpha=0.05 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=22+20-2=40  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505  

P value  

Since is a bilateral test the p value would be:  

p_v =2*P(t_{40}>0.505)=0.61633  

Comparing the p value with the significance level \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.  

3 0
3 years ago
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