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laiz [17]
4 years ago
14

Solve using the multiplication principle.​ Don't forget to perform a check.

Mathematics
2 answers:
barxatty [35]4 years ago
4 0
48=6x

Divide both sides by 6

X=48÷6

x=8
Scorpion4ik [409]4 years ago
3 0
X = 8

6 x 8 = 48

hope this helped
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Ben is making waffles for his 3 friends. The recipe
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Answer: The answer is D. Hope it helps.

Step-by-step explanation:

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I need help with this question please
ikadub [295]

Answer:

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Write 2.3181818 as a mixed number​
kolezko [41]

Hey there!☺

Answer:\boxed{2\frac{1590909}{5000000}}

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3 years ago
Y-12=4y solve for y and show work plz
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7 0
3 years ago
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The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 – 5t2, where t is the tim
Leno4ka [110]
<h2>Time Interval : 1 sec to 1.414 sec</h2>

Step-by-step explanation:

       The height of the stuntperson jumping off a 20\text{ }m is modelled as h\text{ }=\text{ }20\text{ }-\text{ }5t^{2}. Here t is the time in seconds.

       We have to record the person when he is between the heights 15\text{ }m\text{ and }10\text{ }m from the ground.

       When h\text{ }=\text{ }15,

               15\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }5\\t^{2}\text{ }=\text{ }1\\t\text{ }=\text{ }1\text{ }sec

       When h\text{ }=\text{ }10,

               10\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }10\\t^{2}\text{ }=\text{ }2\\t\text{ }=\text{ }\sqrt{2}\text{ }=\text{ }1.414\text{ }sec

       The stuntperson is at height 15\text{ }m at t\text{ }=\text{ }1\text{ }sec, and is at height 10\text{ }m at t\text{ }=\text{ }1.414\text{ }sec.

∴ The camera should film the person for the time interval \textbf{1}\text{ }sec\text{ to }\textbf{1.414}\text{ }sec.

5 0
3 years ago
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