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Step2247 [10]
3 years ago
7

Triangle ABC is isosceles. What are the steps you would take to construct the perpendicular bisector for segment AB.​

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

look at my Step-by-step explanation

Step-by-step explanation:

The perpendicular bisector of a line segment

open the compass more than half of the distance between A and B, and scribe arcs of the same radius centered at A and B.

Call the two points where these two arcs meet C and D. Draw the line between C and D.

CD is the perpendicular bisector of the line segment AB. Call the point where CD intersects AB E.

Proof. top.

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ycow [4]

<u>Answer-</u>

<em>Area of the triangle is </em><em>10 sq.units</em>

<u>Solution-</u>

We know that,

\text{Area of the triangle}=\dfrac{1}{2}[{x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]

Taking,

(x₁, y₁) = (3, 3)

(x₂, y₂) = (3, -1)

(x₃, y₃) = (-2, -5)

Then putting these in the formula,

\text{Area of the triangle}=\dfrac{1}{2}[3(-1+5)+3(-5-3)-2(3+1)]

=\dfrac{1}{2}[3(4)+3(-8)-2(4)]

=\dfrac{1}{2}[12-24-8]

=\dfrac{1}{2}[-20]

=-10

As area can not be negative, ignoring negative sign,

\text{Area of the triangle}=10

6 0
3 years ago
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pochemuha

Answer:

hi

Step-by-step explanation:

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Step-by-step explanation:

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