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3 years ago

Write an equation in slope-intercept form of a line that contains points (2-4) and (5,8)

Mathematics

1 answer:

Svetllana [295]3 years ago

8 0

Answer:

y = 4x - 12

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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The lcm of 2 numbers is 60 and one of the numbers is 7 less than the other number

brilliants [131]

The two numbers are 5 and 12.

6 0

3 years ago

Two buses leave towns 576 kilometers apart at the same time and travel toward each other. One bus travels 12

KIM [24]

Answer:

Rate of slower bus; 90 km/h

Rate of faster bus; 102 km/b

Step-by-step explanation:

We know that formula do distance is;

Distance = speed/time

We are told that One bus travels 12h slower than the other.

Let speed of slower bus be x.

Thus;

Speed of faster bus = x + 12

Speed of slower bus = x

After 3 hours, distance by faster bus = 3(x + 12)

Speed of slower bus = 3x

Since the towns are 576 km apart, then;

3(x + 12) + 3x = 576

Divide through by 3 to get;

x + 12 + x = 192

2x + 12 = 192

2x = 192 - 12

2x = 180

x = 180/2

x = 90 km/h

Faster bus speed = 90 + 12 = 102 km/h

8 0

2 years ago

A rectangle is four times as long as it is wide. If its length were diminished by 6 meters and its width were increased by 6 met

valkas [14]

Answer:

Length equals 16 and Width equals 4

Step-by-step explanation:

First let us create an equation. We can use L and W for length and width.

If the length is 4 times the width, then we end up with: L = 4W

It then says, " If its length were diminished by 6 meters and its width were increased by 6 meters, it would be a square."

Since a square has an equal length and width then we end up with:

L - 6 = W + 6

Knowing this we can just substitute the first equation into the second one leaving us with: 4W - 6 = W + 6

We then remove a W from both sides so that the right side is left with a 6, and add 6 to both sides to remove the -6 from the left one.

This leaves us with 3W = 12

W = 4, and if we put that into our first equation, L = 4W, then Length equals 16, and Width equals 4. We can check this by putting it into the 2nd equation. 16 - 6 = 4 + 6.

7 0

1 year ago

Unsure how to do this calculus, the book isn't explaining it well. Thanks

krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

1 year ago

10 points! I will thanks, rate, and give best answer!!

vfiekz [6]

Answer: The fourth term is -102

----------------------------------------------

Explanation:

The term after the nth term is generated by this rule $a_{n+1} = -4(a_n) + 2$ which means that we first
Step 1) multiply the nth term ( $a_n$ ) by -4
Step 2) Add the result of step 1 to the value 2 to get the next term in the sequence

Let's follow those steps above to generate the first four terms

The first term is $a_1 = 2$ . In short, the first term is 2

The second term is...
$a_{n+1} = -4(a_n) + 2$
$a_{1+1} = -4(a_1) + 2$
$a_{2} = -4(2) + 2$
$a_{2} = -8 + 2$
$a_{2} = -6$
So the second term is -6

The third term is...
$a_{n+1} = -4(a_n) + 2$
$a_{2+1} = -4(a_2) + 2$
$a_{3} = -4(-6) + 2$
$a_{3} = 24 + 2$
$a_{3} = 26$
The third term is 26

Finally, the fourth term is...
$a_{n+1} = -4(a_n) + 2$
$a_{3+1} = -4(a_3) + 2$
$a_{4} = -4(26) + 2$
$a_{4} = -104 + 2$
$a_{4} = -102$
The fourth term is -102.

4 0

3 years ago